16x^2+50x=225

Solution for 16x^2+50x=225 equation:

16x^2+50x=225

We move all terms to the left:

16x^2+50x-(225)=0

a = 16; b = 50; c = -225;
Δ = b2-4ac
Δ = 502-4·16·(-225)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-130}{2*16}=\frac{-180}{32}
=-5+5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+130}{2*16}=\frac{80}{32}
=2+1/2
$